Answer:
17.86 m
Explanation:
The first step is to find the velocity of the swimmer.
Velocity, v = s/t
Velocity, v = 5 / 0.27
Velocity, v = 18.52 m/s
Then, we find the height
h = ½gt²
h = ½ * 9.8 * 0.27²
h = 4.9 * 0.0729
h = 0.36 m
Next, we apply the law of conservation of energy
mgH = mgh + ½ mv²
9.8Hm = m(9.8 * 0.36 + 0.5 * 18.52²)
9.8H = 3.528 + 171.4952
9.8H = 175.02
H = 175.02 / 9.8
H = 17.86 m
Therefore, the needed height is 17.86 m
Answer:
Energy loss ΔE = 8.08 (Approx)
Explanation:
Given:
Channel width = 8 m/s²
Before jump a1 = 0.50 m
After jump a2 = 4.75 m
Find:
Energy loss ΔE
Computation:
Energy loss ΔE = (a2 - a1)³ / 4a1a2
Energy loss ΔE = (4.75 - 0.50)³ / 4(4.75)(0.50)
Energy loss ΔE = 76.7656 / 9.5
Energy loss ΔE = 8.08 (Approx)
The three types of magnets are temporary, permanent, and electromagnets.
Answer:0.246 m
Explanation:
Given
height of window (h)=1 m
Time to pass window =0.28 s
Let roof is at a distance of 
above window
let t be the time to cover
------1
--------2
subtract 1 & 2
![1=\frac{g}{2}\left [ \left ( 2t+0.28\right )\left ( 0.28\right )\right ]](https://tex.z-dn.net/?f=1%3D%5Cfrac%7Bg%7D%7B2%7D%5Cleft%20%5B%20%5Cleft%20%28%202t%2B0.28%5Cright%20%29%5Cleft%20%28%200.28%5Cright%20%29%5Cright%20%5D)
t=0.224 s
