Question

The noise from a power mower was measured at 104 dB. The noise level at a rock concert was measured at 121 dB. Find the ratio of the intensity of the rock music to that of the power mower.

Answer 1

Based on the calculations, the ratio of the intensity of Ir to Ip is equal to 50.12.

How to find the ratio of the intensity?

• Let the intensity of the power mower be Ip.

• Let the intensity of the rock music be Ir.

Mathematically, sound intensity level can be calculated by using this formula:

$\beta = 10 log(\frac{I}{I_{ref}} )$

Where:

I is the intensity of the sound.

Making I the subject of formula, we have:

I = Io × $10^{\frac{\beta }{10} }$

For Ip, we have:

Ip = Io × $10^{\frac{104 }{10} }$

Ip = Io × $10^{10.4}$

For Ir, we have:

Ir = Io × $10^{\frac{121 }{10} }$

Ir = Io × $10^{12.1}$

Now, we can find the ratio of the intensity:

Ir/Ip = Io × $10^{12.1}$/Io × $10^{10.4}$

Ir/Ip = $10^{12.1}$/$10^{10.4}$

Ir/Ip = $10^{12.1 -10.4}$

Ir/Ip = $10^{1.7}$

Ir/Ip = 50.12.

Read more on sound intensity here: brainly.com/question/17062836

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