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3 years ago

10

Disabling asthma attacks can lead to restrictive school activity of approximately

1 answer:

mamaluj [8]3 years ago

7 0

Answer:

<h2>Yes.</h2>

Explanation:

If we want to "disable" astham attacks, that would imply too many restictions for those people who can suffer from these attacks. For example, in order to avoid these attacks, they couldn't do sport activities, because that would alter their respiratory system, which occasionate astham attacks.

Therefore, this statement is true.

You might be interested in

True or False: If your gas pedal jams, you should turn the key to lock to lock the steering wheel.

Bond [772]

Answer:False

Explanation:

Turn the key to lock is not advisable as it lock the steering wheel and may create a dangerous situation.

Following steps can be taken in this situation

Try to press the brake to stop the vehicle
Shift gear to neutral in order to cease the acceleration of car.
Try to lift the gas pedal in order to decrease the velocity of car.

5 0

3 years ago

Read 2 more answers

How much did the temperature change between 10 a.m. and 1 p.m.?

yanalaym [24]

First take note that you're figuring 10am and 1pm. Their temperatures are 77 degrees and 83 degrees

To solve subtract 83-77=6

So it rose 6 degrees.

4 0

4 years ago

A generator connected to an RLC circuit has an rms voltage of 140 V and an rms current of 31 mA. Part A

vredina [299]

Answer:

53.06 ohm

Explanation:

We have given the rms voltage V =140 V

And the rms current i=31 mA

So the impedance $Z=\frac{V}{i}=\frac{140}{3\times 10^{-3}}=46.666kohm$

Resistance is given as R = 3 kohm

And capacitive reactance $X_C=6.5kohm$

We know that $Z=\sqrt{R^2+(X_L-X_C)^2}$

$46.666=\sqrt{3^2+(X_L-6.5)^2}$

Squaring both side $2177.1556=9+(X_L-6.5)^2$

$(X_L-6.5)^2=2168.155$

$(X_L-6.5)=46.5634$

$X_L=53.063ohm$

8 0

3 years ago

A car starts from rest and accelerates with a constant acceleration of 1.00 m/s2 for 3.00 s. The car continues for 5.00 s at con

barxatty [35]

Answer:

19.5 m

Explanation:

Using the equation of motion,

For the first 3 seconds,

s = ut +1/2at².......................... Equation 1

Where t = time, u = initial velocity, a = acceleration, s = distance

Note: Since the car starts from rest, u = 0 m/s.

Given: a = 1.0 m/s, t = 3 s, u = 0 m/s

Substitute into equation 1

s = 0×3+1/2(3)²(1)

s = 9/2

s = 4.5

In the remaining five seconds, at a constant velocity,

s' = vt............. Equation 2

Where v = velocity, t = time.

Recall,

v = u+at

v = 0+1(3)

v = 3 m/s.

Also, t = 5 s.

Substitute into equation 2

s' = 3(5)

s' = 15 m.

Total distance = 15+4.5

Total distance = 19.5 m.

Hence the car travels 19.5 m

8 0

3 years ago

A 5 kg mass is moving at 3 ms-1. Calculate its kinetic energy.

cupoosta [38]

Answer:

1/2 MV squared

1/2*5*3 squared

=22.5

8 0

3 years ago