Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Answer:
C
Step-by-step explanation:
x^2 + (x+3)^2 = 117
x^2 + x^2+6x+9 =117
2x^2 + 6x - 108 = 0
(2x-12)(x+9)=0
x=-9,6
x cannot be negative therefore, x = 6
Answer:ok I’ll join
Step-by-step explanation:
5.5-3b = 2b-6.25
5.5+6.25 = 2b+3b
11.75 = 5b
11.75/5 = 5b/5
2.35 = b
