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VladimirAG [237]
3 years ago
5

What is a counterexample of the following conjecture any number that is divisible by 3 is also divisible by 6

Mathematics
1 answer:
Bess [88]3 years ago
6 0

Any odd multiple of 3 would be the counterexample of the given conjecture.

That is 3(2n - 1), for any natural number n, will be divisible by 3 but not divisible by 6 as 2 is not a factor.

<u>Examples:</u>

3(3) = 9

3(5) = 15

3(7) = 21 are some examples.

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Hey!

-----------------------------------------------

Steps To Solve:

4.6(x - 3) = -0.4x + 16.2

~Distributive property

4.6x - 13.8 = -0.4x + 16.2

~Add 0.4 to both sides

4.6x - 13.8 + 0.4= -0.4x + 16.2 + 0.4

~Simplify

5x - 13.8 = 16.2

~Add 13.8 to both sides

5x - 13.8 + 13.8 = 16.2 + 13.8

~Simplify

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Divide 5 to both sides

5x/5 = 30/5

~Simplify

x = 6

-----------------------------------------------

Answer:

\large\boxed{x~=~6}

-----------------------------------------------

Hope This Helped! Good Luck!

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