What is a counterexample of the following conjecture any number that is divisible by 3 is also divisible by 6
1 answer:
Any odd multiple of 3 would be the counterexample of the given conjecture.
That is 3(2n - 1), for any natural number n, will be divisible by 3 but not divisible by 6 as 2 is not a factor.
<u>Examples:</u>
3(3) = 9
3(5) = 15
3(7) = 21 are some examples.
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2 is the correct answer....gitty up