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4 years ago

What is a counterexample of the following conjecture any number that is divisible by 3 is also divisible by 6

Mathematics

1 answer:

Bess [88]4 years ago

6 0

Any odd multiple of 3 would be the counterexample of the given conjecture.

That is 3(2n - 1), for any natural number n, will be divisible by 3 but not divisible by 6 as 2 is not a factor.

<u>Examples:</u>

3(3) = 9

3(5) = 15

3(7) = 21 are some examples.

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3 years ago

A square that measures 2 inches by 2 inches.<br> What is the perimeter of the square?

natali 33 [55]

Answer:

Step-by-step explanation:

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3 years ago

PLS HELPPP MEEEEEEEEE

LenaWriter [7]

Answer:

x= 7

B= 112

F= 68

Step-by-step explanation:

to find x we set up an equation, (16x)=(4x+84). They are alternate interior angles which are always equal.

calculate it and you'll find x=7.

B and the angle 4x+84 are equal because they are vertical angles, to find it we just put 7 instead of x into 4x+84.

4(7)+84=112

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3 years ago

A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let

Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1 are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

$x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5$

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

$x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0$

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of $X_1-X_2$ is a normal distribution.

Mean =

$100 - 105 = -5$

Standard error =

$\sqrt{\displaystyle\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\\\\=\sqrt{\displaystyle\frac{(1.5)^2}{25} + \frac{(2)^2}{30}}\\\\= 0.473$

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3 years ago