Can you find angle a

Can anybody help me solve this ?

qaws [65]

Answer:

77*

First we are going to take our given number, 25* and 78* and add them together.

25* + 78* = 103*

And subtract our answer, 103*, from 180*.

180* - 103* = 77*

77* is our missing angle. To prove it, we add angle measures a, b, and c, to make the number 180*

25* + 78* + 77* = 180*

Another way to write it is . . .

180* - (A + B) = C

~Hope this helps~

5 0

3 years ago

PLEASE HELP! I DON'T UNDERSTAND!

Ivanshal [37]

just count by 60's until you get close to 852 and each 60 is 1 bracelet

3 0

3 years ago

Read 2 more answers

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. • If t

son4ous [18]

Answer:

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

There is a 15.87% probability of failure of the cable.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. This means that $\mu = 75, \sigma = 20$ .

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

This is the pvalue of Z when $X = 50$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 75}{20}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1056.

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

Now we have that

$X = 0.2(30) + 0.35(50) + 0.45(70) = 55$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 75}{20}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587.

There is a 15.87% probability of failure of the cable.

3 0

3 years ago

Solve the system<br> 4x + 2y = 10<br> x = y + 13

Maslowich

Answer:

$x = 6$

$y = -7$

Step-by-step explanation:

We have the system of equations:

$4x+2y=10\\x=y+13$

Let's solve by substituting. We know that $x=y+13$ , so we can substitute $y+13$ in as $x$ in the equation $4x+2y=10$ .

$4(y+13) + 2y = 10$

Simplify this down so that we have $y$ on one side of the equation:

$4y + 52 + 2y = 10\\\\6y + 52 = 10\\\\6y = -42\\\\y = -7$

Now that we know the value of $y$ , we can substitute it in to the equation $x = y+13$ to find $x$ .

$x = -7+13\\\\x = 6$

Hope this helped!

3 0

3 years ago

Read 2 more answers

David cast a shadow 42" long at the same place and time in Emma cast a shadow 28" long. David is 66" tall. What is Emma's height

Nikolay [14]

ANSWER

Emma is 44" tall

EXPLANATION

We have that David cast a shadow 42 inches long and he is 66 inches tall.

At that same place and time, Emma cast a shadow of 28 inches.

Since they are at the same spot and time, we can conclude that the ratio of their height to shadow must be the same.

Let Emma's height be x.

The ratio of David's shadow to height is:

42 : 66 or 42 / 66

For Emma, it is:

28 : x or 28 / x

That means that:

$\begin{gathered} \frac{42}{66}\text{ = }\frac{28}{x} \\ \text{Solve for x by cross-multiplying:} \\ 42\cdot\text{ x = 66 }\cdot\text{ 28} \\ x\text{ = }\frac{66\cdot\text{ 28}}{42} \\ x\text{ = 44 inches} \end{gathered}$

So, Emma is 44" tall.

3 0

1 year ago

Can you find angle a​

Can you find angle a