3 years ago

What Is the midpoint of the line segment with endpoints (1, -6) and (-3, 4)?

1 answer:

8 0

Slope = m = -1x length = |-3-2| = 5y length = |4-(-1)| = 5The other endpoint is to the left in this case.The end point (xn,yn) = (-3-5,4+5)=(-8,9)So (-8,9) is the other endpoint

You might be interested in

I gotta stop using this websites( i need help)

erastovalidia [21]

Answer:

V:100.8

SA:111

Step-by-step explanation:

7 0

2 years ago

the legs of a right triangle measure 5 inches and 7 inches if the theta is the the angle between the 5 inch leg and hypotenuse,

Goryan [66]

First find the hypotenuse.

a^2 + b^2 = c^2

5^2 + 7^2 = c^2

c^2 = 25 + 49

c = sqrt(74)

sin(theta) = opp/hyp

sin(theta) = 7/(sqrt(74))

7 0

3 years ago

Evaluate (mm)(x) for x=-3

Korolek [52]

Step-by-step explanation:

Maybe

(m²)(-3)

-3m²

hope it helps

8 0

3 years ago

Hey, Its the same person. This is Algebra 2. Please Help!

suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = $\frac{2x^2+5x-12}{x+4}$ ← factorise the numerator

= $\frac{(x + 4)(2x-3)}{x+4}$ ← cancel (x + 4) on numerator/ denominator

= 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

There is a zero at ( $\frac{3}{2}$ , 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( $\frac{3}{2}$ , 0 )

7 0

3 years ago

Hiii please help i’ll give brainliest if you give a correct please please thank youuuuu

Finger [1]

Answer: 24 boxes of pens

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers