We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
Answer:
They have a 0 in the ones place
Step-by-step explanation:
Because you start with 10, you will always have a 0 at the end.
30, 90, 270, etc.
Answer:
It would depend on how many miles per gallon your car gets
Step-by-step explanation:
As a general rule, most cars have about 2.5 gallons left in the tank when the gas light comes on. So depending on how many miles you get per gallon, you can probably go anywhere between 30-60 miles.
Answer: A. 15
Explanation:
n is equal to 15 because 15 divided by 5 is 3. therefore, 3 = 15/5.