Answer:
90 different ways
Step-by-step explanation:
We have a total of 10 members, and we want to find how many groups of 2 members we can have, where the order of each member in the group of 2 is important, so we have a permutation problem.
To solve this problem, we need to calculate a permutation of 10 choose 2.
The formula for a permutation of n choose p is:
So we have:
So there are 90 different ways of choosing a president and a vice-president.
Answer:
12 fish
Step-by-step explanation:
You need to work this problem backwards. If he caught 30 fish, which was six more than twice the number he caught last year, you would start by subtracting six, leaving you with 24. Then you'd have to divide by 2, because it was twice plus six as many fish, which would give you 12 fish.
= x
= x
12 = x
Answer:
-24 - 57i
Step-by-step explanation:
i'm assuming that this is a question about imaginary numbers and that i²= -1
we can expand the binomial by using the FOIL method (see attached)
(6 − 7i)(3 − 6i)
= (6)(3) + (6)(-6i) + (-7i)(3) + (-7i)(-6i)
=18 - 36i - 21i + 42i² (recall that i²= -1)
= 18 - 57i + 42(-1)
= 18 - 57i - 42
= -24 - 57i
