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mrs_skeptik [129]
3 years ago
13

If a couple plans to have seven children, what is the probability that there will be at least one boy?

Mathematics
2 answers:
jolli1 [7]3 years ago
8 0
1/2 chance of one baby being a boy
1/2*7
7:2 chance
tresset_1 [31]3 years ago
7 0
A 3 1/2 chance it will be a boy

(I just put 7 in half)
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Coco's garden has 888 tomato plants, 444 pepper plants, 333 squash plants, and 666 pumpkin plants.
AveGali [126]
888 + 444 + 333 + 666 = 2331 / 7 = 3

3 * 222 = 666

There are 666 of the plants 

I hope this helps :)
6 0
3 years ago
Read 2 more answers
Prove: If n is a positiveinteger and n2 is<br> divisible by 3, then n is divisible by3.
notka56 [123]

Answer:

If n^2 is divisible by 3, the n is also divisible by 3.

Step-by-step explanation:

We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then, n^2 is not divisible by 3.

Let n not be divisible by 3. Then \frac{n}{3} can be written in the form of fraction \frac{x}{y}, where x and y are co-prime to each other or in other words the fraction is in lowest form.

Now, squaring

\frac{n^2}{9} = \frac{x^2}{y^2}

Thus,

n^2 = \frac{9x^2}{y^2}

\frac{n^2}{3} = \frac{3x^2}{y^2}

It can be clearly seen that the fraction \frac{3x^2}{y^2} is in lowest form.

Hence, n^2 is not divisible by 3.

Thus, by contrapositivity if n^2 is divisible by 3, the n is also divisible by 3.

5 0
3 years ago
7. A letter from the word PERSONALITY and a card from a standard deck are chosen at random. How many outcomes are possible?
yKpoI14uk [10]

Answer:

11

Step-by-step explanation:

There are more than eleven cards in a deck but there can only be one outcome because there are only 11 letters in the word PERSONALITY.

8 0
3 years ago
A ferritin test is a popular test to measure a person’s current iron stores. in women, ferritin is normally distributed with a m
MArishka [77]
Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation

Random variable, x = 100
To test P(x < 100), calculate the z-score.
 z = (x-μ)/σ = (100 - 89)/23 = 0.4783

From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%

Answer: 68.4%
7 0
3 years ago
What is the conditional relative frequency of selling an item marked 50% off, provided the item sold is item 2?
sukhopar [10]

Answer:

Conditional relative frequency = 0.67

Step-by-step explanation:

               50% off        Buy 1, get 1 free      Total

Item 1         12                       8                      20

Item 2         20                      10                     30

Total           32                      18                     50

Condition relative frequency table:

               50% off        Buy 1, get 1 free      Total

Item 1         \frac{12}{20}=0.6             \frac{8}{20}=0.4            \frac{20}{20}=1

Item 2        \frac{20}{30}=0.67           \frac{10}{30}=0.33          \frac{30}{30}=1

Total            \frac{32}{50}=0.64           \frac{18}{50}=0.36          \frac{50}{50}=1

Therefore, conditional relative frequency of selling an item marked 50% off, provided the item sold is item 2 = 0.67

8 0
3 years ago
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