One year, the population of a city was 400,000. Several years later it was 340,000. Find the percent decrease.

Last question , thanks!!! so much

bezimeni [28]

Answer: (1,3)

Step-by-step explanation:

Find the place where the two lines cross. That’s your answer! It’s (1,3).

3 0

3 years ago

Read 2 more answers

What is the equation of a line (in slope-intercept form) with a slope of -1 and a y

crimeas [40]

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

What we know:

slope: -1

y-intercept: 0.7

Therefore:

m = -1

b = 0.7

Plug the values of <em>m </em>and <em>b </em>in y = mx + b:

y = -1x + 0.7

OR

y = -x + 0.7

OR

y = 0.7 - x

^^^These are all written in slope intercept form but just in different ways

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

3 years ago

Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)

weeeeeb [17]

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

We have the final answer as

Hope this helps you

8 0

2 years ago

Samaria attached 165 inches of fringe material to a tablecloth if the tablecloth was in a shape of a regular pentagon how much f

Y_Kistochka [10]

35 in. because a pentagon has 5 sides and have to divide the total amount of yarn to the sides.

4 0

3 years ago

the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region

m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

$\frac{x}{360} \pi {r}^{2}$

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

$16 = \sqrt{10 {}^{2} + 10 {}^{2} - 2(100) \times \cos(o) }$

This isn't the standard formula, it's for this problem

$16 = \sqrt{200 - 200 \times \cos(o) }$

$16 = \sqrt{200 - 200 \cos(o) }$

$256 = 200 - 200 \cos(o)$

$56 = - 200 \cos(o)$

$- \frac{7}{25} = \cos(o)$

$\cos {}^{ - 1} ( - \frac{7}{25} ) = \cos {}^{ - 1} ( \cos(o) )$

$106.26 = o$

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

$\frac{106.26}{360} (100)\pi$

$\frac{10626}{360} \pi$

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

$\frac{36}{2} = 18$

$\sqrt{18(18 - 10)(18 - 10)(18 - 16)}$

$\sqrt{18(8)(8)(2)}$

$\sqrt{(36)(64)}$

$6 \times 8 = 48$

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

$\frac{10626}{360} - 48$

Which is an approximate or

44.73

6 0

2 years ago