Step-by-step explanation:
Hey there!
Here;
The equations are;


Multiplying equation (i) by 2.
16x + 14y = 78
<u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>4</u><u>y</u><u> </u><u> </u><u> </u><u>=</u><u> </u><u>-68</u>
20x = 10

x = 1/2.
Putting value of 'x' in equation (i).




Therefore the value of y is 5.
<u>Check</u><u>:</u>
<u>Put</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>and</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u>.</u>
8x + 7y = 39



(True).
<u>Therefore</u><u>, </u><u>the</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>;</u><u> </u><u>(</u><u>1</u><u>/</u><u>2</u><u>,</u><u>5</u><u>)</u><u>.</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer: Commutative property of multiplication
Step-by-step explanation: The problem 6 · 1 = 1 · 6 demonstrates the commutative property of multiplication.
In other words, the commutative property of multiplication says that changing the order of the factors does not change the product.
So for example here, 6 · 1 is equal to 6 and 1 · 6 also equals 6.
Since 6 = 6, we can easily see that 6 · 1 must be equal to 1 · 6.
In more general terms, the commutative property of multiplication can be written as a · b = b · a where <em>a</em> and <em>b</em> are variables that can represent any numbers.
The area of a circle is given by

We can solve this equation for r: divide both sides by pi:

Consider the (positive) square root of both sides:

So, in your case, we have

Because we don't have any set numbers for x or y, I believe that the solution set for both equations are infinite.