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2 years ago

The ratio of the measures of the angles in a triangle is 2:9:4 what is the measure of the largest angle ?

Mathematics

2 answers:

Anna007 [38]2 years ago

6 0

180 degrees..... szjsisisjaak

FrozenT [24]2 years ago

5 0

You need to add all of these values together. This is 2 + 9 + 4 which gives 15

There are 180° in a triangle. Divide this by 15.

180/15 = 12

Then multiply this by the largest in the ratio; which is 9.

This is 12 x 9 which = 108°.

The largest angle is therefore 108°.

For reference, the ratio in degrees would look like this:

24:108:48, which adds up to 180°.

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Fantom [35]

Answer:

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c is phase shift

d is vertical shift or midline.

In the equation equation, we must factor out 2 so we get

$y = - 6(2(x + \frac{\pi}{4} )) + 3$

Also remeber a and b is always positive

So now let answer the questions.

a. The period is

$\frac{2\pi}{ |b| }$

$\frac{2\pi}{ |2| } = \pi$

So the period is pi radians.

b. Amplitude is

$| - 6| = 6$

Amplitude is 6.

c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.

So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].

D. Plug in 0 for x.

$3 - 6 \sin((2(0) + \frac{\pi}{2} )$

$3 - 6 \sin( \frac{\pi}{2} )$

$3 - 6(1)$

$3 - 6$

$= - 3$

So the y intercept is (0,-3)

E. To find phase shift, set x-c=0 to solve for phase shift.

$x + \frac{\pi}{4} = 0$

$x = - \frac{\pi}{4}$

Negative means to the left, so the phase shift is pi/4 units to the left.

f. Period is PI, so use interval [0,2pi].

Look at the graph above,

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