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laila [671]
3 years ago
6

Marked price = Rs 650 and Discount percentage = 2.5%. find selling price​

Mathematics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

The selling price is <u>Rs.633.75</u>.

<h3><u>Solution</u> :</h3>

Here we have given that :

  • \pink\star Marked Price = Rs.650
  • \pink\star Discount % = 2.5 %

We need to find the selling price.

Firstly, finding the discount by substituting the values in the formula :

{\longrightarrow{\sf{Discount = Marked \:  Price \times  Discount \%}}}

{\longrightarrow{\sf{Discount =650\times 2.5\%}}}

{\longrightarrow{\sf{Discount =650\times  \dfrac{2.5}{100}}}}

{\longrightarrow{\sf{Discount = \dfrac{650 \times 2.5}{100}}}}

{\longrightarrow{\sf{Discount = \dfrac{1625}{100}}}}

{\longrightarrow{\sf{Discount = 16.25}}}

Hence, the discount is Rs.16.25.

\rule{200}2

Now, finding the selling price by substituting the values in the formula :

{\longrightarrow{\sf{Selling \:  Price = Marked \:  Price -  Discount}}}

{\longrightarrow{\sf{Selling \:  Price = 650 - 16.25}}}

{\longrightarrow{\sf{Selling \:  Price =633.75}}}

Hence, the selling price is Rs.633.75.

\rule{300}{2.5}

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Talia sells educational software for a yearly salary of $65,000 plus a 2.65% commission on her total sales. If Talia sells $2.5
Bad White [126]

Answer:

$131250

Step-by-step explanation:

Talia's earnings during one year are equal to her base yearly salary ($65000) added to her commission. Now, to know the commission it is necessary to find the 2.65% of her total sales ($2.5 million)

Step 1. Divide the total sales or 2,500,000 by 100 considering this represents the total or 100%

2,500,000 ÷ 100 = 25000

Step 2. Multiply this number by the specific percentage (2.65)

25000 x 2.65 = 66250

Now add the commission and the yearly salary

65000 + 66250 = 131250

Hence, total earnings of Talia were $131250

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If 18 is subtracted from twice the square of an integer, the
Sergeu [11.5K]

Answer:

-3/2

Step-by-step explanation:

Let x = the integer:

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Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"
dsp73
For any scalars c_1,c_2, we have

c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w

So

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w

We have

\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}
=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k
=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k
=\begin{bmatrix}-60\\9\\76\end{bmatrix}

which makes

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}
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