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nlexa [21]
3 years ago
7

Round the answer to the nearest cent. 5% tax on $20 is $

Mathematics
1 answer:
adoni [48]3 years ago
4 0
5% tax on 20 dollars.
First let's convert 5% to decimal
=> 5% / 100 = .05
Next is to simply multiple 0.05 to 20 dollars
=> 20 * .05 = 1 dollar.
Thus. the 5% of 20 dollars is 1 dollar.
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One number exceeds another by 24. The sum of the numbers<br> is 58. What are the numbers?
Anna35 [415]
X + x + 24 = 58
x = (58-24)/2=17
the first number is 17 and the second number is the sum of 17 and 28. Finding it has been left as an exercise for the reader.
3 0
3 years ago
Find the equation in slope-intercept form that describes a line through (2, 4) with slope 0
True [87]

Since we already know that the slope is 0, x cancels out in the equation.

y = mx + b → y = b

We just need to find the y-intercept. Using the coordinate (2, 4) we can substitute with y.

4 = b

Hence, the answer is b) y = 4

Hope This Helped! Good Luck!

6 0
3 years ago
Trapezoid JKLM is shown below.
Alecsey [184]
B is the answer because you have to math it
5 0
3 years ago
HELP ME PLEASEEEEEEEEEEEEEEEEEEE
faust18 [17]

Answer:

it would be the cube

Step-by-step explanation:

When you imagine the cube it has 6 faces and 12 edges

3 0
3 years ago
Read 2 more answers
b) If parametric equations of a flow line are x = x(t), y = y(t), explain why these functions satisfy the differential equations
sineoko [7]

Answer:

The equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1.

Step-by-step explanation:

The pathline equation for a vector field is given by F(x,y) = xî - yj

The velocity vector field for the streamline of the flow is given by

V(x, y) = (dx/dt)î + (dy/dt)j

From the question, it is given that

(dx/dt) = x

(dy/dt) = -y

Hence, the velocity vector field for the streamline of the flow in question is

V(x, y) = xî - yj

which coincides with the pathline vector field of the flow.

The only time the pathline and streamline vector field coincide and have the same equation is when the flow is a steady state flow.

That is, the properties of the fluid flowing isn't changing with time!

Hence, this flow is a steady state flow!

We're told to solve the differential equation.

(dx/dt) = x

(dy/dt) = -y

but

(dy/dx) = (dy/dt) × (dt/dx)

(dy/dx) = -y/x

(dy/y) = -(dx/x)

∫(dy/y) = -∫ (dx/x)

In y = - In x + c

where c is the constant of integration

In y + In x = c

In (xy) = c

Inserting the values of (x, y) given in the question,

In (-1 × -1) = c

In 1 = c

0 = c

c = 0

In y + In x = 0

In (yx) = 0

xy = e⁰ = 1

xy = 1

So, the equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1

Hope this Helps!!!

4 0
3 years ago
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