Answer:
The correct answer to this question is option (1).
Explanation:
Let x1 = Is number of pages that printer A can print in page/minute.
thus x1 + 5 = Is number of page that printer B can print in page/minute.
As printer A finishes his work in 60 min. So the task has 60x1 pages. As printers A and B both finish that task in 24 minutes. So the equation can be given as:
60x1 = 24x1 + 24(x1 + 5)
60x1 = 24x1 + 24x1 + 120
60x1=48x1 + 120
60x1-48x1=120
12x1=120
x1=120/12
x1=10
put the value of x1 in to (60x1). Therefore, the task has 60(10) = 600 pages. the task contains 600 pages.
So the answer to this question is option (1).
The system of rules and structure which governs language is generally referred to as: C. grammar.
<h3>What is language?</h3>
A language simply refers to a structured system of communication through which living organisms, especially humans share information among themselves, especially through the use of spoken words and sounds.
In English language, grammar is the system of rules and structure which governs the use and composition of language.
Read more on language here: brainly.com/question/781903
#SPJ1
Answer:
Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.
;Include Irvine32.inc file used with link library for 32 bit applications
.386
.model flat,stdcall
.stack 4096
ExitProcess proto,dwExitCode:dword
INCLUDE Irvine32.inc
.data
myArray DWORD 0,2,5,9,10
arrSize = ($-myArray)/TYPE myArray
gapArr DWORD arrSize-1 DUP(?)
sum DWORD ?
.code
main PROC
;Call the procedure
call Clrscr
;Initialize ESI pointer
mov esi, 0
mov ecx, arrSize
dec ecx
L1:
mov eax, myArray[esi+4]
sub eax, myArray[esi]
mov gapArr[esi], eax
inc esi
loop L1
;Calculate the sum of gaps between array elements
mov sum, 0
mov esi, 0
mov ecx, arrSize
dec ecx
; move gapArr[esi] to a temporary register and then add that register value to sum
L2:
mov edx, gapArr[esi]
add sum, edx
inc esi
loop L2
INVOKE ExitProcess,0
main ENDP
END main
Explanation:
Answer:
gpresult
Explanation:
Group Policy provides the system administrator with settings that would be necessary to manage the different user accounts available in an organization. It also controls their work environment centrally by configuring the user Operating System (OS), applications and user accounts.
Group policy settings or configurations are referred to as Group Policy Objects (GPOs). These objects can be linked to organizational units (OUs), domains or sites.
There are various group policy commands such as;
- rstrui (System Restore tool will run),
- runas (using different permission to run a tool or program),
- tasklist (currently running programs are shown
- gpupdate (Group policies are refreshed)
- gpresult (group policy configurations are displayed for verification)
gpresult command can be used to verify the group policy configurations for adjustment or optimization. The technician can start troubleshooting from viewing the active settings, then running the rstrui to start the System Restore utility to restore the computer to an earlier date
the answer to this is 2 and 3
Hope this helped
-scav
