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butalik [34]
3 years ago
8

What is the area of a square if s = 8 inches?

Mathematics
2 answers:
Mashutka [201]3 years ago
6 0

Answer:

The area of the square is 64 inches^2

Step-by-step explanation:

Area of a square formula:  A = a^2

<u>Step 1:  Since the side is 8, plug it into the little a </u>

A = a^2

A = (8)^2

<em>A = 64 </em>

Answer:  The area of the square is 64 inches^2

asambeis [7]3 years ago
5 0

Answer:

64 ins

Step-by-step explanation:

8*8=64

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The measure of ∠FDE = 18°

<u>Explanation:</u>

A Pentagon has 5 sides and is made of 3 triangles

So, sum of the interior angles of the triangle = 180°

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If tanx = 0.75, what is the value of cosx + sinx ?
kap26 [50]
Cosine (x) = 4 over 5
cos
(
x
)
=
4
5
Explanation:
First you must apply sohcahtoa
it means
sine = opposite side over hypotenuse
sine = opposite/hypotenuse
cosine = adjacent side over hypotenuse
cosine = adjacent/hypotenuse
tangent = opposite side over adjacent side
tangent = opposite/adjacent
then
solve the unknown by applying the Right Triangle Theorem.
draw a right triangle.
label the parts where
a
is the opposite side
b
is the adjacent side
c is the hypotenuse
Solve the unknown. The hypotenuse using
a
2
+
b
2
=
c
2

since the given
tan
x
=
3
4

it means
tan = opposite/adjacent
a
= opposite side =
3

b
= adjacent side =
4

c
= hypotenuse = ??
a
2
+
b
2
=
c
2

substitute the value
(
3
)
2
+
(
4
)
2
=
c
2

9
+
16
=
c
2

25
=
c
2

get the square root of
25

it is equal to
5

therefore
c
=
5

c
= hypotenuse =
5

cos
= adjacent/hypotenuse
cos
(
x
)
=
4
over
5

cos
(
x
)
=
4
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