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tatuchka [14]
3 years ago
15

Gold and helium are examples of a(n)

Chemistry
2 answers:
LUCKY_DIMON [66]3 years ago
6 0
Gold and helium are examples of elements
Ann [662]3 years ago
6 0
They are both examples of an element. Hope this helps!
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What is the concentration of each type of monosaccharide in lactose
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Answer:

Lactose comprises the monosaccharides glucose and galactose and maltose, comprising two glucose molecules, which occurs in barley, wheat, and malt.

Explanation:

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How much would a 10 kg suitcase weigh on the surface of…? a. The Moon b. Mars c. Saturn d. Pluto
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Is this the full question

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2 years ago
What is the difference between weight and mass?
Marina86 [1]

Key differences between Mass and Weight

The weight may vary, but the mass is constant.

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3 years ago
Your teacher asks you to design an experiment that shows how plants respond to changes in their environment. You have two identi
tia_tia [17]

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

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Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

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6 0
3 years ago
Read 2 more answers
In going from room temperature (25 C) to 10 C above room temperature, the rate of reaction doubles. Calculate the activation ene
Sauron [17]

Answer:

Ea=5.29 × 10⁴ J/mol

Explanation:

In going from 25 °C (298 K) to 35 °C (308 K), the rate of the reaction doubles. Since the rate of the reaction depends on the rate constant (k), this implies that the rate constant doubles. We can find the activation energy (Ea) using the two-point form of the Arrhenius equation.

ln\frac{k_{2}}{k_{1}} =\frac{-Ea}{R} .(\frac{1}{T_{2}}-\frac{1}{T_{1}})\\ln\frac{2k_{1}}{k_{1}}=\frac{-Ea}{8.314J/K.mol}.(\frac{1}{308K}-\frac{1}{298K} )\\Ea=5.29 \times 10^{4} J/mol

8 0
3 years ago
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