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KIM [24]
4 years ago
6

Sodium hydroxide, NaOH, is a strong base that is used in industrial synthesis and processes such as making paper. What is the ma

ss of 2.60 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
Chemistry
2 answers:
Ghella [55]4 years ago
7 0
Answer : Mass would be = 1.859 g for NaOH

Explanation : 
We have got 2.88 X  10^{22} molecules of NaOH,

so we get,

\frac{2.88 X 10^{22} moles of NaOH }{6.022 X 10^{23}/mol } X 40.0 g of NaOH/mol

On solving we get, answer as 1.859 g

Hence the g of NaOH will be 1.86.
elena-14-01-66 [18.8K]4 years ago
3 0
  The  mass of 2.60 x10^22  molecules of NaOH  is   1.728   grams

calculation
 mass = moles  x molar mass
   molar mass = 40 g/mol

mole   is calculated   using the Avogadro   law
that is  1 mole =   6.02 x10^23 molecules
              ?        =  2.60  x10 ^ 22  molecules

by   cross   multiplication

 (1 mole x  2.60  x10^22) /  6.02 x0^23  =  0.0432  moles

mass   is therefore= 0.0432  mole x  40 g/mol = 1.728 grams
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True or false the strength and concentration of an acid or base describe the same property.
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I’m pretty sure that it’s true.
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How much heat is needed to vaporize 10.00 grams of water at 100.0°c? the latent heat of vaporization of water is 2,259 j/g. 22.5
puteri [66]

The correct option is:

The latent heat of vaporization of water is given by option D. 22,590J

Latent heat of vaporization:

Latent heat of vaporization is energy required to change 1 kg of liquid to gas at atmospheric pressure at its boiling point.

Also, Latent heat is the energy released or absorbed during a phase change.

Energy released during phase change is Exothermic process.

Whereas energy absorbed during phase change is Endothermic process.

Q=mL

Q= Latent heat

m= mass= 10 g

L= Latent heat of vaporization= 2,259 J/g

Putting the values in the above equation:

Q=10*2259

Q=22590 L

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8 0
2 years ago
2. How many moles of hydrogen atoms are there in 154 mL of 0.18 M H2SO4? Write your
katrin [286]

2. 0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. 15.2506 heat in Joules is absorbed by 150.0 mL of pure water that is heated from 21.2°C to  45.5°C.

4. 0.75 M is the concentration of Na+ ions in 25.0 mL of 1.50 M NaOH is reacted with 25.0 mL of  1.50 M HCI

Explanation:

Number of moles of H2SO4 can be calculated by the given volume and molarity from the formula:

molarity = \frac{number of moles}{volume of teh solution}

number of moles = molarity × volume of the solution of H2SO4

    number of moles = 0.18 × 0.154 litres

                                   = 0.02772 moles of H2SO4.

Since 1 mole of H2SO4 contains 2 moles of hydrogen

so, 0.02772 moles of H2SO4 will have x moles

\frac{1}{2} = \frac{0.0272}{x}

2 × 0.02772 = x

0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. The heat absorbed is calculated from the formula:

ΔH = cp × m × ΔT   ( ΔT = change in temperature in Kelvin, m in kg, cp= specific heat of water)

putting the values in formula:

ΔH = 4.184 × 0.15 × ( 318.65-294.35)

     =  4.184 × 0.15× 24.3

        = 15.2506 Joules of heat is absorbed.

4. The concentration of Na+ ions

the balanced equation is

NaOH + HCl⇒ NaCl + H20

from one mole of NaCl 1 mole of NaCl i.e one 1 mole of Na+ ions is formed.

number of moles of NaOH is calculated by the formula:

Molarity = \frac{number of moles}{volume of the solution}

number of moles = 0.025L × 1.50M

                             = 0.0375 moles of NaOH

so 1 mole of NaOH produces 1 mole of Na= ions

hence, 0.0375 moles produces x moles of Na+ ions

\frac{1}{1} = \frac{0.0375}{x}

moles of Na+ is produced.  

concentration of NaOH in 50 ml solution because NaOH and HCl of 25 ml reacted.

applying the molarity formula from above

Molarity =  \frac{0.0375}{0.05}

              =  0.75 M

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Gennadij [26K]

Answer:

The answer is 4.

Explanation:

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