A neutralization process is a reaction between an acid and a base which yields a salt and water. From the choices, a neutralization reaction would be: 2 HBr + Ca(OH)2 yields CaBr2 + 2 H2O. Moreover, <span>NH3 + HCl yields NH4Cl is also a neutralization reaction. The complete reaction is actually NH4OH + HCl --> NH4Cl + H2O. NH4OH is the aqueous solution of NH3. This reaction is still a neutralization reaction.
On the other hand, the reaction </span><span>HCl + HBr yields H2 + ClBr is not valid. There is no reaction between HCl and HBr because both are strong acids. They would just dissociate into ions like H+, Cl- and Br-.
The valid reaction that is clearly not a neutralization process is </span><span>H2 + Br2 yields 2 HBr. This is a combination reaction yielding a strong acid HBr.</span>
Answer:The answers are on the attachments.
Explanation:
The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.
<h3>Why is the energy released in a reaction?</h3>
Energy is released in a reaction due to the breaking of bonds are well as formation of bonds.
The quantity of energy released in reactions differs according to the reaction type involved.
When compared to chemical reactions, the energy released in nuclear reactions are very much higher because of the changes that occurs in the nucleus of the atoms involving nuclear energy.
The energy, E released in nuclear reactions is given by the formula below:
where m is the mass of the substance and c is the speed of light.
Therefore, the energy released in nuclear reactions are far larger than that released in chemical reactions.
Learn more about nuclear reactions at: brainly.com/question/984564
Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>
Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48
K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span>
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M)
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075
NH3 = 0.44 M
