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2 years ago

11

Solve for x. Assume that segments that appear to be tangent are tangent. Round your final answer to the nearest tenth, if necess

ary.

1 answer:

Butoxors [25]2 years ago

6 0

Answer:

x= 16.6

Step-by-step explanation:

The circle is unnecessary. You can just use Pythag Theorem

so

9^2+14^2= c^2

81 + 196 = 277

square root 277

16.64

round to the nearest tenth...

16.6

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Pls help me i just need help

Ray Of Light [21]

Step-by-step explanation:

the total cost is, of course, first the cost to buy the copier, and then the running costs per copy made.

it is really that easy.

the equations just put this into mathematical form :

A

y = 0.02×x + 800

B

y = 0.06×x + 600

please notice, we put $600 or $800 in as constant term, because these costs are the starting costs that we have, even if we never make a single copy (x = 0).

and then the total cost goes up with every copy we make.

I cannot draw here.

so, to find the number of copies where both copier systems would cost the same, means we have to say both equating deliver the same result :

0.02×x + 800 = 0.06×x + 600

200 = 0.04×x

x = 200 / 0.04 = 5000

when making 5000 copies both costs are the same.

4 0

2 years ago

Quizizz 10 pts each help please WITH PIC brainiest guaranteed

lawyer [7]

Answer:

2. $-2m^4-6m^2+4m+9$

3. $-2m^4-6m^2-4m+9$

Step-by-step explanation:

<em>In general we can write a polynomial in standard form as </em>

$ax^n+bx^n^-^1+cx^n^-^2+...+px+q$

<em>Given</em> $4m-2m^4-6m^2-4m+9$

<em>Combine the like terms: 4m and -4m</em>

<em>4m-4m=0</em>

<em>We have 4m-4m=0</em>

<em>So, write the remaining terms</em>

$-2m^4-6m^2+9+0$

= $-2m^4-6m^2+9$

<em>This is in decreasing order of powers.</em>

<em>Hence the answer is the standard form is</em>

$-2m^3-6m^2+9$

<em>But in the given options, you can choose option 2 and option 3 are in standard form.</em>

<em>Because they are in decreasing order of powers.</em>

<em>In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.</em>

<em>-2m^4-6m^2+4m+9</em>

<em>-2m^4-6m^2-4m+9</em>

<em>I hope this helps you.</em>

<em>And please comment if I need to do corrections.</em>

<em>Please let me know if you have any questions.</em>

8 0

3 years ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

so

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

3 years ago

TechWiz Electronics makes a profit of $35 for each MP3 player sold and $18 for each DVD player sold. Last week, TechWiz sold a c

Blababa [14]

(35x+18)=126. I think this is right not for sure

4 0

3 years ago

Read 2 more answers

50 POINTS What are the values of a1 and r of the geometric series? 2 – 2 + 2 – 2 + 2

torisob [31]

Answer:

a1=2 and r=-1

Explanation:

"A geometric series is a series with a constant ratio between successive terms".

Here, we can observe that the first term 'a' is '2'.

And the common ratio 'r' =

Therefore, the first term 'a' is 2 and common ratio 'r' is '-1'.

8 0

3 years ago

Read 2 more answers