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3 years ago

:()))()()((;(;((()))))))))))))))))))

Mathematics

2 answers:

kupik [55]3 years ago

8 0

6. a + 14
7. 10x
8. 3m+3n

leonid [27]3 years ago

8 0

Answer: 1. 2a+14

2.10x

3.3m+3n

Step-by-step explanation: Hope this helps!

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Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

$\underbrace{ \overbrace {\mathfrak{Carry \: On \: Learning}}}$ ☂

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5 0

3 years ago

PLEASE FOR 100 POINTS!!! PLEASE!!!

tiny-mole [99]

Answer:

$\Large \boxed{\sf 956.56 \ mm^2}$

Step-by-step explanation:

Surface area → area of 2 bases + area of 6 rectangles

Area of base is given

Area of rectangle → length × width

$\left(2\cdot 166.28\right)+\left(8\cdot 13\cdot 6\right)=956.56$

3 0

3 years ago

Read 2 more answers

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d

kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0

3 years ago

What is the slope and y-intercept of the following equation: 5x - 3y = 36

bazaltina [42]

Answer:

y=5/3x-12

slope= 5/3

y-intercept= -12

Step-by-step explanation:

i hope this helps :)

4 0

2 years ago

Read 2 more answers

What is f(8)=0.8(8)^2

Montano1993 [528]

Answer:

f = 5.12

Step-by-step explanation:

f(8)=0.8(8)^2

f(8)=6.4^2

f(8)=40.96

f(8)/8 = 40.96/8

f = 5.12

i'd really appreciate being marked brainliest if you want! i appreciate it :)

7 0

3 years ago