Tan60=x/12 12tan60=14.3 so area formula: 85.8
Answer:
the dimensions of the most economical shed are height = 10 ft and side 5 ft
Step-by-step explanation:
Given data
volume = 250 cubic feet
base costs = $4 per square foot
material for the roof costs = $6 per square foot
material for the sides costs = $2.50 per square foot
to find out
the dimensions of the most economical shed
solution
let us consider length of side x and height is h
so we can say x²h = 250
and h = 250 / x²
now cost of material = cost of base + cost top + cost 4 side
cost = x²(4) + x²(6) + 4xh (2.5)
cost = 10 x² + 10xh
put here h = 250 / x²
cost = 10 x² + 10x (250/ x² )
cost = 10 x² + (2500/ x )
differentiate and we get
c' = 20 x - 2500 / x²
put c' = 0 solve x
20 x - 2500 / x² = 0
x = 5
so we say one side is 5 ft base
and height is h = 250 / x²
h = 250 / 5²
height = 10 ft
First move the 4y to the right and the 1 to the left:
4y=5x-1
Then divide everything by 4:
y=5/4 x - 1/4
Answer:
5x+4y = 52
Step-by-step explanation:
We can first write the equation in point slope form
y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point
y - 8 = -5/4 ( x-4)
Multiply each side by 4 to get rid of the fraction
4(y - 8) = 4*(-5/4) ( x-4)
4(y - 8) = -5 ( x-4)
Distribute
4y - 32 = -5x+20
We want the equation in the form
Ax + By = C
Add 5x to each side
5x+4y -32 = -5x+5x+20
Add 32 to each side
5x+4y -32+32 =32+20
5x+4y = 52
