15(cos 206° + i sin 206°) answer in a+bi form
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Assuming it equals 0
for
ax^2+bx+c=0
x=
given
5x^2+2x-3=0
a=5
b=2
c=-3
x=
x=
x=
x=
x=(-2+8)/10 or (-2-8)/10
x=6/10 or -10/10
x=3/5 or -1
for
ax^2+bx+c=0
x=
given
5x^2+2x-3=0
a=5
b=2
c=-3
x=
x=
x=
x=
x=(-2+8)/10 or (-2-8)/10
x=6/10 or -10/10
x=3/5 or -1