5.3/8.8=x/14.3
AB is x,
x= 2.43
Hope I helped.
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
The last one is not scientific notation because the 25.67 is greater than 10
Answer:
The number of heads observed is 121.14 heads
Step-by-step explanation:
The formula for the z-score of a proportion is given as follows;
Where:
= Sample proportion
p = Population success proportion = 0.5
q = 1 - p = 1 - 0.5 = 0.5
n = Number in of observation = 200
z = 2.99
Hence, we have;
Therefore;
= 0.6057
∴ The number of heads observed = 200 × 0.6057 = 121.14 heads.
