Question

Find the area of a triangle with a =33, b =51, and c =42.

Answer 1

Answer:

d. 690.1 units²

Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

$K=\sqrt{s(s-a)(s-b)(s-c)}$

Where:

$s=\frac{a+b+c}{2}$

2. Calculate $s$:

$s=\frac{33+51+42}{2}\\s=63$

3. Substitute values into the formula shown above and calculate the area, as following:

$K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}$

4. Therefore, the area is 690.1 units².