Answer:
Simplify the denominator.
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x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
x
2
−
5
x
+
6
Factor
x
2
−
5
x
+
6
using the AC method.
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x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
(
x
−
3
)
(
x
−
2
)
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
(
x
+
3
)
(
x
−
3
)
,
(
x
−
3
)
(
x
−
2
)
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
The number
1
is not a prime number because it only has one positive factor, which is itself.
Not prime
The LCM of
1
,
1
is the result of multiplying all prime factors the greatest number of times they occur in either number.
1
The factor for
x
+
3
is
x
+
3
itself.
(
x
+
3
)
=
x
+
3
(
x
+
3
)
occurs
1
time.
The factor for
x
−
3
is
x
−
3
itself.
(
x
−
3
)
=
x
−
3
(
x
−
3
)
occurs
1
time.
The factor for
x
−
2
is
x
−
2
itself.
(
x
−
2
)
=
x
−
2
(
x
−
2
)
occurs
1
time.
The LCM of
x
+
3
,
x
−
3
,
x
−
3
,
x
−
2
is the result of multiplying all factors the greatest number of times they occur in either term.
(
x
+
3
)
(
x
−
3
)
(
x
−
2
)
Step-by-step explanation:
there does that help
For six you can write 1/4 because there is 4 pennies and 1 represents each penny
for number 5 you can put 2/10 because there is 10 coins and 2 quarters
and for number 7 is that Bradley has 10 coins not 9 so it would be 1/10
Step-by-step explanation:
1.
true
false
false
true
2.
yes
no
yes
no
yes
3.
A
4.
7,5 $
Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
