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navik [9.2K]
3 years ago
14

Plz help im helping my brother :)

Mathematics
2 answers:
likoan [24]3 years ago
7 0

Answer:

d

Step-by-step explanation:

Tju [1.3M]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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The value of x is about 6.1538 
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A research analyst for a car rental agency found that the probability distribution function for the age of the rental car (in ye
alexdok [17]

Answer:

10 years

Step-by-step explanation:

Given

Decline from (0,h) to (10,0)

See attachment for graph

Required

Determine the age when height = 0

The function of the graph is represented as: (age, height)

So, we need to read from the graph the corresponding value of age (on the x-axis) when height = 0 (i.e. the y-axis)

From the attached graph;

age = 10 when height = 0

<em>Hence, the age of the car is 10 years</em>

4 0
3 years ago
Little help, please thank you
Vitek1552 [10]

Answer:

Finding volume:

2^2 = 4

4 x 3.14 = 12.56

12.56  x 8(height) = 100.48

100.48 divided by 3 ( x 1/3 ) =  around 33.49 in3 is your answer.

If the options dont give you 33.49 just go by 33.51 cubic meters.

8 0
3 years ago
What is midpoint of the segment whose endpoints are (-2,-3) and (6,1)?
denis23 [38]
(-2+6)/2=x
(4)/2=x
2=x
(-3+1)/2=y
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3 0
3 years ago
A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia
Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and  irrespective of the order.

{n\choose k}=\frac{n!}{k!(n-k)!}

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

^{n}P_{k}=\frac{n!}{(n-k)!}

In this case we need to select two different cards from a pack of 52 cards.

  • Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{52\choose 2}=\frac{52!}{2!(52-2)!}

      =\frac{52\times 51\times 50!}{2!\times50!}\\=1326

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

  • Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

^{n}P_{k}=\frac{n!}{(n-k)!}

^{52}P_{2}=\frac{52!}{(52-2)!}

       =\frac{52\times 51\times 52!}{50!}

       =52\times 51\\=2652

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0
3 years ago
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