Answer: 2years, 5 months
Step-by-step explanation:
Principal, P = $6000
Rate, R = 3%
Interest, I = $450
Time, T =?
Simple Interest, I = P x T x R/ 100
making T, subject of formula
T = 100 x I/ P x T
Substituting the values into the equation,
T = 100 x 450/ 6000 x 3
T = 45000/ 18000
T = 2.5years = 2years, 5 months
Fret seems like the best option.
Answer:
C
Step-by-step explanation:
A and B have initial value of 100 and D is a quadratic equation
Subtract 363,321 from 778,871. Which gives you 415,550 more geese than crows :)
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
