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vivado [14]
3 years ago
15

Marshall's & Co. purchased a corner lot in Eglon City five years ago at a cost of $640,000. The lot was recently appraised a

t $670,000. At the time of the purchase, the company spent $30,000 to grade the lot and another $3,200 to build a small building on the lot to house a parking lot attendant who has overseen the use of the lot for daily commuter parking. The company now wants to build a new retail store on the site. The building cost is estimated at $1,110,000. What amount should be used as the initial cash flow for this building project?'
Business
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

$1,780,000

Explanation:

The computation of the initial cash flow for this building project is shown below:

= Estimated building cost + appraised cost of the lot

= $1,110,000 + $670,000

= $1,780,000

Simply we added the estimated building cost and the appraised cost of the lot so that the initial cash flow amount can come.

All other information which is given is not relevant. Hence, ignored it

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Rose Marie received $152 in earned income and $25 in transfer payments.

Explanation:

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Health Valley is a brand of food, such as breakfast cereals, that uses all natural and organic ingredients. Moreover, it only pu
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The correct answer is letter "A": green marketing.

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7 0
3 years ago
Suppose the world population today is 7 billion, and suppose this population grows at a constant rate of 3% per year from now on
oksano4ka [1.4K]

Answer:

a) P(t=100) = 7 e^{0.03*100}=140.599 billion

b) P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

c) Figure attached

d) Figure attached

Explanation:

The proportional model on this case would be given by:

\frac{dP}{dt} = kP

Where P is the population size, t the time on years and k a constant.

We can reorder this expression like this:

\frac{dP}{P} = k dt

If we integrate both sides we got:

ln|P| = kt + C

And using exponentials on both sides we got:

P(t) = e^{kt} e^C = P_o e^{kt}

Where P_o=7 billion  represent the initial amount for the starting year t=0.

The rate on this case is given r =3\% = 0.03, so then our model would be given by:

P(t) = 7 e^{0.03t}

Part a

For this case we just need to replace t=100 and we got:

P(t=100) = 7 e^{0.03*100}=140.599 billion

Part b

For this case we have the following:

P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

Part c

The graph is on the first figure attached.

Part d

If we take a log-log scale we have the following values

We need to exclude the point t=0 since the natural log for 0 is not defined.

ln 1 =0 , ln 2= 0.693, ln 10=2.30, ln 25 =3.22, ln 50= 3.91

The result would be the figure 2 attached. And we see a better result for the graph.

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Whats 10. Budget ???????????????????????????????
Masja [62]

It's a f<span>inancial plan that reflects anticipated revenue and shows how it will be allocated in the operation of the business.. :)</span>

7 0
3 years ago
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