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vivado [14]
3 years ago
15

Marshall's & Co. purchased a corner lot in Eglon City five years ago at a cost of $640,000. The lot was recently appraised a

t $670,000. At the time of the purchase, the company spent $30,000 to grade the lot and another $3,200 to build a small building on the lot to house a parking lot attendant who has overseen the use of the lot for daily commuter parking. The company now wants to build a new retail store on the site. The building cost is estimated at $1,110,000. What amount should be used as the initial cash flow for this building project?'
Business
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

$1,780,000

Explanation:

The computation of the initial cash flow for this building project is shown below:

= Estimated building cost + appraised cost of the lot

= $1,110,000 + $670,000

= $1,780,000

Simply we added the estimated building cost and the appraised cost of the lot so that the initial cash flow amount can come.

All other information which is given is not relevant. Hence, ignored it

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Opal Inc. used $213,000 of direct materials and incurred $111,000 of direct labor costs during 2015. Indirect labor amounted to
alex41 [277]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

4 0
3 years ago
A public authority that provides banking services to co m m ercial banks and regulates financial institutions and m arkets is ca
Savatey [412]

Answer:

C ) central bank.

Explanation:

Central bank is also known as banker's bank or bank for commercial banks. They are custodians of cash reserves of commercial banks and lenders too. Commercial banks also store a percentage of it's deposit with commercial banks.

5 0
3 years ago
Zhao Co. has fixed costs of $429,000. Its single product sells for $187 per unit, and variable costs are $122 per unit. If the c
otez555 [7]

Answer:

$635,000 and : 34%

Explanation:

Margins of safety is the difference between expected sales and the break-even point.

For Zhao, expected sales are 10,000 units

The break-even points in units = fixed cost/ contribution margin per unit

fixed costs = $429,000

Contribution margin per unit = selling price - variable costs per unit

=$187 -  $122

=$65

break-even point in units = $429,000/$65

break-even point = 6600 units

Margin of safety = 10,000 - 6600 units

=3400 units

In dollars is equal to margin of safety in units x selling price

=3400 x 187

<u>=$635,000</u>

as a percent of expected sales.

=3400/10000 x 100

=0.34 x 10,000

=34%

4 0
3 years ago
Until recently, hamburgers at the city sports arena cost $ 2.50 each. The food concessionaire sold an average of 1750 hamburgers
Artyom0805 [142]

Answer:

  (A) p = -0.002x +6; 0 ≤ x ≤ 3000

  (B) R(x) = x(6 -0.002x); 0 ≤ x ≤ 3000

  (C) C(x) = 1.44x +1903

  (D) (550, 2695), (1730, 4394.20)

  (E) P(x) = -0.002x^2 +4.56x -1903

  (F) increasing at $2.16 per hamburger

Explanation:

(A) The two-point form of the equation for a line can be used.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

The two points we have are ...

  (x, p) = {(1750, 2.50), (1450, 3.10)}

so the equation is ...

  p = (3.10 -2.50)/(1450 -1750)/(x -1750) +2.50

  p = 0.6/-300(x -1750) +2.50

  p = -0.002x +6

The domain of this function is where x and p are greater than 0. That will be for ...

  0 ≤ x ≤ 3000

__

(B) Revenue is the product of burgers sold (x) and their price (p).

  R(x) = xp

  R(x) = x(6 -0.002x)

The domain of R(x) is 0 ≤ x ≤ 3000. This is the same as the domain of p(x).

___

(C) The cost function is the sum of fixed costs and variable costs:

  C(x) = 1.44x +1903

__

(D) See the attachment for a graph of cost and revenue. The break-even points are (x, revenue) = (550, 2695), (1730, 4394.20).

__

(E) Profit is the difference between revenue and cost.

  P(x) = R(x) - C(x) = x(6 -0.002x) -(1.44x +1903)

  P(x) = -0.002x^2 +4.56x -1903

__

(F) The marginal profit is the derivative of the profit function:

  P'(x) = -0.004x +4.56

  P'(600) = -0.004(600) +4.56 = -2.40 +4.56 = 2.16

At a production level of 600, the profit is increasing at a rate of $2.16 per hamburger.

6 0
3 years ago
an annual bond selld for $865 with par value $1,000 and coupoin rate 8% what is bond yeild to maturity for 10 years
lisov135 [29]

Answer:

1.4484 %

Explanation:

The formula for Yield to Maturity =

[C + (FP - MP) /n]/FP + MP/2

Where

C = Coupon rate = 8% = 0.08

MP = Market value or price = $865

FP = Face or Par value = $1000

n = number of years = 10

Yield to Maturity =[ 0.08 +(1000 - 865) /10]/ 1000 + 865/2

Yield to Maturity = 1.4484 %

5 0
3 years ago
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