Answer:
1.778 times more or 16/9 times more
Step-by-step explanation:
Given:
- Mirror 1: D_1 = 8''
- Mirror 2: D_2 = 6"
Find:
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?
Solution:
- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:
LGP ∝ A
- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:
A ∝ D^2
- Hence, LGP ∝ D^2
- Now compare the two diameters given:
LGP_1 ∝ (D_1)^2
LGP ∝ (D_2)^2
- Take a ratio of both:
LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2
- Plug in the values:
LGP_1/LGP_2 ∝ (8)^2 / (6)^2
- Compute: LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more
The solution to the system of linear equations is where the two lines intersect.
Look for the point where the two lines intersect. The x-value is 2 1/2, and the y-value is -4.
The answer is C.
X = y + 5
-y + x - x = y - y + x + 5
-y = x + 5
y = x - 5
Answer:
Solution set {x|x<8}
Step-by-step explanation:
0.35x - 4.8<5.2- 0.9x
0.35x+0.9x<5.2+4.8
1.25x<10
x<10/1.25
x<8
Solution set {x|x<8}
