Answer:
The equation in point-slope is 
Step-by-step explanation:
We need to write the point-slope form of the equation of the line passing through the point (6,-5) and perpendicular to the line 
The general form of point-slope is; 
where m is slope and 
is the point
We need to calculate slope.
We are given equation of line that is perpendicular to the required line.
The equation is given in slope-intercept form 
where m is slope.
Comparing both equations we get m= -1/3
But we know that when lines are perpendicular their slopes are opposite reciprocal of each other i.e 
<em>So, </em><em>slope of required line is m = 3 </em><em>(opposite reciprocal of -1/3)</em>
Now, the equation in point-slope form having slope m=3 and point (6,-5) is
So, The equation in point-slope is
Answer:
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Step-by-step explanation:
5z^2−9z=−7z−5
We need to get all the terms on one side (set the right side equal to zero)
Add 7z to each side
5z^2−9z+7z=−7z+7z−5
5z^2−2z=−5
Add 5 to each side
5z^2−2z+5=−5 +5
5z^2−2z+5=0
This is in the form
az^2 +bz+c = 0 so we can use the quadratic formula
where a = 5 b = -2 and c = 5
-b± sqrt(b^2-4ac)
-------------------------
2a
-(-2)± sqrt((-2)^2-4(5)5)
-------------------------
2(5)
2± sqrt(4-100)
-------------------------
10
2± sqrt(-96)
-------------------------
10
2± sqrt(16)sqrt(-1) sqrt(6)
-------------------------
10
2± 4i sqrt(6)
-------------------------
10
1/5 ± 2/5 i sqrt(6)
Splitting the ±
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Answer:The answer is 4/28 is greater.
Step-by-step explanation:
Answer:
2$ I think
Step-by-step explanation:
I think the answer is 6. ABC, ACB, BAC, BCA, CAB, and CBA.
