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lana66690 [7]
3 years ago
14

Solve I=PRT for P if I=312.50, r=25%, and T=0.25

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer: I = $ 19.53

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 25%/100 = 0.25 per year,

then, solving our equation

I = 312.5 × 0.25 × 0.25 = 19.53125

I = $ 19.53

The simple interest accumulated

on a principal of $ 312.50

at a rate of 25% per year

for 0.25 years is $ 19.53.

Umnica [9.8K]3 years ago
3 0

Answer:

P = 5000

You need to multiply r and T together, then divide 312.50 by that.

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Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

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============================================================

Explanation:

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y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

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y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

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Use this to find 'a'

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11111nata11111 [884]

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a geometric sequence means we multiply the previous element by a certain factor to get the next element.

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