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Furkat [3]
3 years ago
12

Help a gorl out y’all

Mathematics
1 answer:
saw5 [17]3 years ago
7 0

Answer

(1/32)^5

Step-by-step explanation:

If you add the exponential power of 5 to both sides of the exponential equation, you will get (1/32)^5, which would be your answer.

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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
2 years ago
Read 2 more answers
Find the greatest commen factor of 96 and 48
kirza4 [7]
48 is the greatest common factor
4 0
3 years ago
Read 2 more answers
Pls some1 help I’ll help u PLSSSS HELP
kakasveta [241]

1/3 is bigger than 30%

4 0
3 years ago
Choose all that correctly solve for the variable x
Ratling [72]
<h2>✔Answer</h2><h2>1. X = 3</h2><h2 /><h2>2. </h2><h2>\frac{7}{2}</h2><h2>3.</h2>

<h2>\frac{5}{6}</h2>

<h2>Hope it Helps❤</h2>
6 0
2 years ago
Hoping to be named Salesperson of the Month, Luther called the names from 1/4 of a page of the phone book last week. This week,
muminat

Answer:

3/4

Step-by-step explanation:

Fraction of names called last week = 1/4 of a page

Fraction called this week = 1/2 of a page

The number of pages worth of people called ;

This is an addition problem, as the total will be the sum. Of the fractions called this week and last week

Hence,

Total page worth of names called :

(1/4 + 1/2) = (1 + 2) / 4 = 3/4

3 0
2 years ago
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