Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Answer:
14) false
15) false
Step-by-step explanation:
14) 120% of a positive whole number is always greater than the number. If the number is 1, 120% of it would give us 1.2 which is greater than 1. However if the number is a negative whole number, 120% of it would give us a smaller number. Let's try -1. 120% of -1 would give us -1.2, which is smaller than -1. Hence the statement is false.
15) 0.5% of a number is 0.5/100 of the number so we should multiply the number by 5/1000. 5/100 is only 5% of the number. Hence the statement is also false.
Which of the tables represents a function ? Table P 8,3 1,7 5,4 Table Q 9,3 9,5 4,2. Table R 7,2 8,6 7,3. Table S 1,7 1,5 9,2 Ta
babymother [125]
Table P because it is a one-to-one relation.
The other 3 are one-to-many relations (eg table Q maps 9 on to 3 and 9 on to 5)
31.
32.
33.
pls mark me as brainliest
Answer:
2/3 (0,-3) is one possible answer.
Step-by-step explanation:
y -1 = 2/3(x-6) We want to get this into the slope intercept form of a line. We want it to be in the form y = mx + b. Let's clear the fraction first by multiplying the whole equation through by 3.
3(y - 1) = 3[2/3(x - 6)]
3y -3 = 2(x -6)
3y - 3 = 2x -12
3y = 2x - 9 Now divide all the way through by 3 to get
y = 2/3x - 3
y = mx + b. The m part is the slope. In this equation the slope is 2/3
There are in infinite amount of points on a line. I do not know if they give you a picture or if you are just to create your own. I am going to create a point that have x = 0. I get to pick the point. I could pick any number. 0 is just usually really easy. So, if I substitute 0 for x I will get:
y = 2/3(0) - 3
y = 1 so my point is (0,-3)
Now that I think about it, I do not think that I would start out clearing the fraction even though it works. I think that I would do it like this"
y - 1 = 2/3(x - 6) Distribute the 2/3 through (x - 4) to get
y-1 = 2/3x -4 I can make -6 a fraction by putting it over 1. Now we have 2/3(-6/1) multiply across to get -12/3. A positive times a negative is a negative. -12 divided by 3 is -4.
y - 1 = 2/3x -4 now add 1 to both sides.
y = 2/3x -3
