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Dmitriy789 [7]
3 years ago
7

Find the difference between -14w - 3 and 5w

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer:

-19w-3

Step-by-step explanation:

-5w from

-14w-3

-19w-3

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Crystal bought a jacket that is $65. She has a coupon for 20% off. She needs to pay 9% tax on the jacket. What is the total amou
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5 0
3 years ago
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The useful life of a radial tire is normally distributed with a mean of 30,000 miles and a standard deviation of 5000 miles. The
otez555 [7]

Answer:

  empirical rule: 81.5%

  table or calculator: 81.9%

Step-by-step explanation:

The lower limit of the life range of interest has a z-score of ...

  z = (x -μ)/σ = (20,000 -30,000)/5,000 = -2

The upper limit has a z-score of ...

  z = (35,000 -30,000)/5,000 = 1

<u>Empirical rule solution</u>

The empirical rule tells you that 95% of the distribution lies within 2 standard deviations of the mean, so (100% -95%)/2 = 2.5% lie below z = -2. It also tells you 68% lie within 1 standard deviation of the mean, so (100% -68%)/2 = 16% lie above z = 1.

The fraction that lies within -2 to 1 standard deviations of the means is thus ...

  (100% -2.5% -16%) = 81.5%

The probability the tire has a life in the desired range is about 81.5%.

__

<u>Calculator solution</u>

A probability calculator for the Normal distribution tells you that ...

  P(-2 < z < 1) ≈ 0.8185946

The probability the tire has a life in the desired range is about 81.9%.

6 0
3 years ago
Is it possible to identify The exact values of all the original service times? A. Yes. The data values in each class are equal t
kakasveta [241]

Answer:

C.

Step-by-step explanation:

The answer to your question would be C. No, the data values in each class could take on any value between the class limits, inclusive.


I hope it helps! Have a great day!

Muffin~

8 0
2 years ago
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A system of equations is shown below.
EastWind [94]

Multiply equation B by 3 and add the result to

equation A.

4 0
3 years ago
A random sample of 65 bags of white cheddar popcorn​ weighed, on​ average, 5.74 ounces with a standard deviation of 0.26 ounce.
Marina86 [1]

Answer:

We failed to accept null hypothesis

Step-by-step explanation:

x= 5.74

Standard deviation = 0.26

H_0:\mu = 5.8\\H_a:\mu < 5.8

n = 65

We will use z test

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

Substitute the values :

z=\frac{5.74-5.8}{\frac{0.26}{\sqrt{65}}}

z=-1.86

Refer the z table for p value

p value = 0.0314

α = 0.10

p value < α

So, we failed to accept null hypothesis

4 0
4 years ago
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