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SpyIntel [72]
3 years ago
15

Which two fractions have a sum of −7/30 ? Drag and drop the appropriate fraction into each box.

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Well you will need two number that are divisible by 30 and add up to -7 so they will have to be a negative.

I would try -2 and -5 which are both divisible by 30 and ad up to -7 so...

-2/30 + -5/30 = -7/30

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almond37 [142]
If there are 36 potato plants, and they are in 4 even rows, that means that there is 9 in each column because 9 x 4 is 36. Since 7 of them were eaten by the sheep and the goat, that means that there are 2 leftover in that row that the sheep and goat got to since 9-7 is 2.
5 0
3 years ago
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I cant figure this one out at all
eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

4 0
2 years ago
Say your car doesn’t run on straight gasoline and you have to mix the oil with gas together in a specific ratio of 2.4 fl oz of
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Answer:

3.6 fl oz

Step-by-step explanation:

figure out the percentage of the gallon that was used in the original ratio, in this case 1 that was used in 1.5. thats 150%

so no multiply 2.4 by 1.5 to get 3.6

to check work divide both ratios and see if its the same number (i checked)

5 0
3 years ago
The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
Rom4ik [11]

f'(x)\ge0 for all x in [-3, 0], so f(x) is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at x=-3.

From the plot, it's clear that on [-3, 0] we have f'(x)=-x. So

f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C

for some constant C. Given that f(0)=7, we find that

7=-\dfrac{0^2}2+C\implies C=7

so that on [-3, 0] we have

f(x)=-\dfrac{x^2}2+7

and

f(-3)=\dfrac52=2.5

5 0
3 years ago
Answer again plsss sorry thanks if you helped
cestrela7 [59]

Answer:

20% and 95%

Step-by-step explanation:

I know this is correct trust me!

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