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Nadya [2.5K]
3 years ago
8

Pls help I am giving brainliest help me ASaP

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

4

Step-by-step explanation:

4 because 4^2 = 16.

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A parking space shaped like a parallelogram has a base of 17 feet and a height is 9 feet. A car parked in the space is 16 feet l
timama [110]
Ok, so we have to find areas and subtract

area=legnth times widht or base times height

parking space area=17 times 9=153
car=16 times 6=96


subtract
153-96=57
answer is 57 ft^2
4 0
3 years ago
Read 2 more answers
If a cyclist races at 30 miles per hour for 1/2 of the distance of a race, and 45 miles per hour for the final 1/2 of the distan
Natasha2012 [34]

Answer:

  36 mph

Step-by-step explanation:

The appropriate relations are ...

  time = distance/speed

  speed = distance/time

Suppose the race has a total length of 360 miles. Then half the race is 180 miles.

The cyclist's time on the first half is (180 mi)/(30 mi/h) = 6 h.

The cyclist's time on the second half is (180 mi)/(45 mi/h) = 4 h.

The total time is 10 h for the total distance of 360 mi, so the average speed is ...

  (360 mi)/(10 h) = 36 mi/h

_____

The length of the race doesn't matter. The above numbers make the math convenient. The average is computed from ...

  1/((1/2)/30 + (1/2)/45) = 2/(1/30 +1/45) = 2·30·45/(30+45) = 36

This is the <em>harmonic mean</em> of the numbers 30 and 45.

7 0
3 years ago
4000 + 12 343 x 2 =(A)
Vikentia [17]

Answer:

12,686

Step-by-step explanation:

add both numbers up then multiply by 2

7 0
3 years ago
A 0.30 kg bird flies in a horizontal curve of radius 20 m at 15 m/s. The force exerted by the air on the bird is about
monitta

Answer:

<h2>b)  3.48 N approx.</h2>

Step-by-step explanation:

<em>The bird will experience a centripetal force, this is the force exerted on a body that moves through a curve path.</em>

F_c = \frac{mv^2}{r}

Fc=centripetal force

m=mass

v=velocity

r=radius

Step one:

given data

mass of bird m=0.3kg

the radius of curve r= 20m

velocity v= 15 m/s

Substituting we have

F_c = \frac{0.3*15^2}{20}\\\\F_c= \frac{0.3*225}{20}\\\\ F_c=\frac{67.5}{20}\\\\F_c=3.37N

<u>The force is 3.37N</u>

7 0
3 years ago
Help meeeeeeeeemejejsjwbjdjwbjiahdd
eimsori [14]
M∠Е = 180 - (54+32) = 94°

18/sin94° = EF/sin54° ⇒
EF = (18*sin54°)/sin94° ≈ 14.6 m

B. 14.6 m

7 0
4 years ago
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