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ELEN [110]
2 years ago
8

Who ever answers this problem incorrect gets brainliest

Mathematics
2 answers:
Ksivusya [100]2 years ago
4 0
Not right meow I’m sleeping sir
Lelu [443]2 years ago
3 0

Answer:

umm there is no problem

Step-by-step explanation:

the answer is 10

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Select the letter that correctly identifies the base of the prism.
Radda [10]

Answer:

I think it's C, I may be wrong though

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Use the pattern below for questions 6 - 8.
Yuliya22 [10]

Answer:

See below

Step-by-step explanation:

<u>The sequence given</u>

  • 6, 19, 58, 175

<u>We see the pattern: triple the previous term plus 1</u>

  • 2) 19 = 6*3 + 1
  • 3) 58 = 19*3 + 1
  • 4) 175 = 58*3 + 1

<u>Next two terms</u>

  • 5) 175*3 + 1 = 526
  • 6) 526*3 + 1 = 1579

<u>Following two terms</u>

  • 7) 1579*3 + 1 = 4738
  • 8) 4738*3 + 1 = 14215

4 0
3 years ago
Number 3 please! pic is above^
zmey [24]

Answer:

Step-by-step explanation:

Slope = (y2 -y1)/(x2-x1)

y2 = 800, y1 = 400, x2= 4, x1= 2

Slope = (800-400)/(4-2)

= 400/2

= 200calories/hr

7 0
3 years ago
At Tanika's school, 3 people are chosen
likoan [24]
Your answer is three out of the people in your school.
5 0
3 years ago
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