Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
Here is you graph
Step-by-step explanation:
:)
To find the experimental probability, you will add the outcomes that resulted in even number and make that a ratio to the total number of outcomes.
<u>(12 + 14 + 18)</u>
(13 + 12 + 12 +14 + 11 + 18)
44/80 = 0.55
0.55 = 55%
The answer is choice D.
Answer: w = 41
QU = 2(RT)
w + 41 = 2w
w = 41
Answer:
f(-4) = -9
Step-by-step explanation:
f(x)=2x-1
Let x = -4
f(-4)=2*-4-1
= -8 -1
= -9
