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1 answer:
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We know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to
degrees.
So,
in this problem
therefore
the answer is
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to
So,
in this problem
therefore
the answer is
Answer:
The equation of the straight line is x - 2y +6 =0
Step-by-step explanation:
<u>Explanation:</u>-
Given a point ( 2, 4) and slope m =
The equation of the straight line passing through the point and having slope 'm'
y - y₁ = m ( x - x₁)
y - 4 = ( x - 2)
2( y -4) = ( x-2)
2 y - 8 = x -2
x - 2 y - 2 + 8 =0
x - 2y + 6 =0
The equation of the straight line is x - 2y +6 =0