V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
Answer:
Step-by-step explanation:
the general equation of a circle is
with (h,k) being the centre of the circle and r the radius
Answer:
8.9k
Step-by-step explanation:
We just have to add together the length of the three sides to find the perimeter of the triangle.
(1.8k-5)+(3.5+6.1k)+(k+1.5) = 1.8k-5+3.5+6.1k+k+1.5
Combine like terms.
1.8k<em>-5+3.5</em>+6.1k+k<em>+1.5</em> = 8.9k <em>+ 0 </em>
= 8.9k
You can try to find a way to get the range from the highest score to the lowest score.
