Can someone show me how to find the product of 3square-root(4) * square-root(3)?
1 answer:
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Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Answer:
The equation that matches the table is y = -5x + 7 ⇒ C
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept (value y at x = 0)
The rule of the slope is m = , where
- (x1, y1) and (x2, y2) are two points on the line
From the given table
→ Choose any two points from the table
∵ Points (0, 7) and (1, 2) are in the table
∴ x1 = 0 and y1 = 7
∴ x2 = 1 and y2 = 2
→ Substitute them in the rule of the slope above
∵ m =
∴ m = -5
→ Substitute it in the form of the equation above
∵ y = -5x + b
∵ b is the value of y at x = 0
∵ At x = 0, y = 7
∴ b = 7
∴ y = -5x + 7
∴ The equation that matches the table is y = -5x + 7