Answer:
45 minutes
Step-by-step explanation:
At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...
t = d/s
t = (7.5 mi)/(10 mi/h) = 0.75 h
to catch Peter.
Mitchell will catch Peter in 45 minutes.
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<em>Alternate Solution</em>
Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:
3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter
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You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.
You will need half of the circle with radius of 15 inches.
Area of semi-circle = (<span>πr^2)/2 = 353.25 x $1.40 = $494.55 </span>
NO.,the given measures can not be the lengths of the sides of a triangle
Step-by-step explanation
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
so, Find the range for the measure of the third side of a triangle given the measures of two sides.
here given measures are 2,2,6
2+2 = 4 which is less than the third side 6
= 4 < 6
This not at all a triangle.
Hence, the given measures can not be the lengths of the sides of a triangle
Answer:
B) 4
Step-by-step explanation:
1. <em>It is either 3 or 4</em>, since those are only two angles comparing the lighthouse and the boat.
2. The angle of depression is noted below the horizontal and above the actual line, and out of 3 and 4, <em>4 is the only angle that is below its corresponding horizontal</em>.
So, the angle of depression from the lighthouse to the boat is 4.
Answer:
The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the y<u>-value.</u>
