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3 years ago

Determine whether or not f is a conservative vector field. if it is, find a function f such that f = ∇

1 answer:

4 0

F =del F, make the distinction its 2 different functions

in this case its a conservative vec field
u can do Del x F or curl F and see its not 0, but anyway, u can also integrate the portion in i wrt to x and portion in j component wrt to y, and see that even with the constants being functions of the variable not being integrated wrt to, you still cannot find a function g such that f(x,y)=del (g)

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Trigonometry<br> y=? x=?

tino4ka555 [31]

Answer:

y=9cm

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Step-by-step explanation:

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2 years ago

A square has an area of 9yd^2. What is the length of each side?

BlackZzzverrR [31]

Answer: The side length is 3 yards.

Step-by-step explanation:

To find the area of a square, you have to square one of it's side lengths since they all share the same length. Since we know the area, and we need to find the side length so we just need to find the square root of the area.

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3 years ago

2. Identify the solution to the system of equations graphed below.

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(-4, 1)

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3 years ago

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Please help ASAP!

Kruka [31]

First, recall that

$\sin(-\theta)=-\sin\theta$

So if $\sin(-\theta)=\dfrac15$ , then $\sin\theta=-\dfrac15$ .

Second,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

We know that $\tan\theta>0$ and $\sin\theta$ , which means we should also have $\cos\theta$ .

Third,

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}$

but as we've already shown, we need to have $\cos\theta$ , so we pick the negative root.

Finally,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}$

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

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Gennadij [26K]

Answer
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2 years ago

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