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lana [24]
3 years ago
9

How can you use greatest common factor and least common multiple to solve problems

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0
By doing 3x4 then you get the answer
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Two-thirds of a class are boys. If there are 12 boys, then<br> how many girls are in the class?
son4ous [18]

Step-by-step explanation:

so 2/3 OF the class are boys...

***REMEMBER IN MATHEMATICS, ^OF^ IS USED TO SAY MULTPLICATION***

so 2/3 OF class(x) are boys and there are 12 boys...

so 2/3 * x = 12

12 / (2/3) = x

to solve use the Keep, Change, Flip method

Keep 12, change / to multiplication, flip 2/3 to 3/2

it becomes 12 * 3/2 and to solve easier 12 is same thing as 12/1

12/1 * 3/2

Multiply across (numerator by numerator and denominator by denominator)

(12*3) / (1*2) = 36 / 2

Simplify

18

So the class has 18 students, and 2/3 of boys (12 of the students)

we can solve for how many girls are in the class

Depending on how your teacher wants to see the work:

either 18 - 12 = 6

or 1/3 * 18 which we rewrite as 1/3 * 18/1 = (1*18)/(3*1) which is 18/3... simplified it is  6

There are 6 girls in the class.

Hope this helps! :)

6 0
2 years ago
Which would not be a step in solving 18=2(4+ x)
mr_godi [17]

Answer:

B

Step-by-step explanation:

Done on apex

8 0
3 years ago
lighting if a 25-foot-tall house cast a 75-foot shadow at the same time that a streetlight casts a 60-foot shadow how tall is th
jolli1 [7]

Answer:

The street light is 20 feet tall.

Step-by-step explanation:

This question depends on a proportion. Keep your height of the object in one ratio and the length of the shadow in the other.

25/x = 75/60      Notice the height of the structure is on the left. The length of the shadow is on the right. Cross multiply

75x =  60 * 25     Combine the right

75x = 1500          Divide by 75

x = 1500/75

x = 20

The street light is 20 feet tall.

3 0
2 years ago
There are seven cats in my neighborhood, with an average of $41$ whiskers each. If one of the cats has $17$ whiskers, how many w
harkovskaia [24]

Answer:

Each of the other cats have 45 whiskers on average.

Step-by-step explanation:

Let x represent the average number of whisker of each cat.

We have been given that there are 7 cats in my neighborhood, with an average of 41 whiskers each.

The total number of whiskers of six cats would be 6x.

Since one of the cats has 17 whiskers, so the total number of whiskers of 7 cats would be 6x+17

We will use average formula to solve our given problem.

\text{Average}=\frac{\text{Sum of data points}}{\text{Number of data points}}

Upon substituting our given values, we will get:

41=\frac{6x+17}{7}

Let us solve for x.

41*7=\frac{6x+17}{7}*7

287=6x+17

287-17=6x+17-17

270=6x

Switch sides:

6x=270

\frac{6x}{6}=\frac{270}{6}

x=45

Therefore, the each of the other cats have 45 whiskers on average.

8 0
3 years ago
Erggkhbqea <br><br>cbse class 7 maths chapter 8 exercise 8.3 solutions in ​
madam [21]

Answer:

am I supposed to join your meet with that C0DE

5 0
2 years ago
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