Which is the equation of a line that has a slope of -7 and a Y intercept of 2

Jakes has $20 to spend on notebooks and pencils the notebooks and pencils. the notebooks cost 3.25 and the pencils cost $.50 wha

Leokris [45]

Hey there. So basically, find out how much the pencils and notebooks cost first.
The notebooks cost = $3.25
The pencils cost = $0.50

Then, think about what you need to figure out in this problem.
Jake has $20. You need to find how many notebooks Jake can buy in maximum after buying 8 pencils.

If Jake buys 8 pencils that costs $0.50 each, he spends $4 on the pencils.

So now, to find out how many notebooks he can buy, do 20 minus 4.
Jake's got $16 left.

If the notebooks cost $3.25 each, we need to find out how many notebooks he can buy by dividing them. So, 16 divided by 3.25 equals 4.923... and so on.

That means, Jake can buy 4 notebooks with his remaining money.

3 0

3 years ago

What number is added to make a perfect square ?

V125BC [204]

Answer:

2 is added

Step-by-step explanation:

5 0

3 years ago

How do i show the work? please help!

asambeis [7]

Tigers: 1 - 2/3 = .3333

Redbirds: 1 - 4/5 = .2

Bulldogs: 1 - 3/8 = .625

Titans: 1 - 1/2 = .5

The Redbirds likelyhood is lowest, therefore, they're least likely to play I'm the championship.

B is the correct answer.

7 0

3 years ago

Chris bought "c" tickets to a movie for $9 each. Michael bought " m" tickets to another movie for $10 each. Write an expression

Fynjy0 [20]

<u>Answer:</u>

9c + 10 (see below)

<u>Step-by-step explanation:</u>

To find how much Chris spent on tickets, you can write an expression to represent the situation:

$9c

You can do this to find how much Michael spent as well:

$10m

To find how much Chris and Michael spent combined, add their two costs:

9c + 10

5 0

3 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago