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sergij07 [2.7K]
3 years ago
9

Sketch the graph of 4x² + 25x – 21 = y using your graphing calculator. What are the x-intercepts of this graph

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

B .75 - 7

Step-by-step explanation:

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What is -2y to the third power when y=-5
MA_775_DIABLO [31]
250, when plugged in, -5 becomes -125, then multiplied by -2 is 250
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Evaluate b^2c^-1 for b=8 and c=-4
HACTEHA [7]
When evaluating b^2c^-1 for b=8 and c=4, the answer is -16

E = b^2c–1
x-a = 1/xa

E = b^2c - 1
= 8^2 x (-4)-1
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2 years ago
Simplify this expression. 17 - 12x - 18 - 5x = ??​
jok3333 [9.3K]
17 -12x - 18 - 5x=
-1 - 17x =
-1 = 17x
3 0
3 years ago
Read 2 more answers
Can the set of lengths be the side lengths of a right triangle?
andreyandreev [35.5K]

Answer:

B. No.

Step-by-step explanation:

We have been given 3 side lengths 7 ft, 12 ft, 17 ft. We are asked to determine, whether the given set of lengths can form a right triangle or not.

We will use Pythagoras theorem to solve our given problem, which states that the square of hypotenuse of a right triangle is equal to the sum of squares of two legs of right triangle.

17^2=12^2+7^2

289=144+49

289>193

Since the sum of  squares of both legs is less than square of hypotenuse, therefore, the given set of lengths can not be the side lengths of a right triangle.

4 0
3 years ago
Read 2 more answers
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
4 years ago
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