Solving for <em>Angles</em>

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>

You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
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Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.
<em>86.20 ft²</em>
- Step-by-step explanation:
<em>Hi there !</em>
<em>A = A₁ + A₂</em>
<em>A₁ =semicircle</em>
<em>A₁ = πr²/2</em>
<em>r = d/2 = 6.4ft/2 = 3.2 ft</em>
<em>A₁ = 3.14×(3.2ft)²/2 ≈ 32.15 ft²</em>
<em />
<em>A₂ = trapezium</em>
<em>A₂ = (b + B)×h/2</em>
<em>A₂ = (5.1ft + 6.4ft)×9.4ft/2 = 54.05 ft²</em>
<em />
<em>A = 32.15 ft² + 54.05 ft² = 86.20 ft²</em>
<em>Good luck !</em>
The answer for your question is A
For a trapezoid:
the area equals the product of half the sum of the two bases' length and the normal height between them
so that, we can write:

Hence <span>the parallel sides are 15 cm apart.
</span>
I hope that
helps!