Answer:
A. 0.22
B. 0.18
C. 0.25
D. 0.244
Step-by-step explanation:
S = {51 to 100} = 50
The sample space S contains values from 51 to 100 which is a total of 50 different values.
A.
Probability of A (lies between the values of 90 to 100 = 11).
11/50 = 0.22
B.
For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.
9/50 = 0.18
C.
For student to get c, (70 to 79) a total of 10 values: 10/50 = 0.20
P(student did not get C) = 1-0.20 = 0.80
To get B, ( 80 to 89)
10/50 = 0.20
Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25
D.
Probability of passing lies between 60 to 100 = 41 scores
41/50 = 0.82
Probability of student who passed having a B = 0.20/0.82 = 0.244
Answer:
If the two linear equations have the same slope, the equations represent the same line. Since a line intersects with itself everywhere, there will be an infinite number of solutions.
Your right it’s an obtuse angle
Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2
Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2
We then add the two areas,
Total Area = 16 + 40 = 56 in^2
Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
