Answer:
(a)
The probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
Step-by-step explanation:
(a)
Case 1
Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

Case 2
Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

Therefore the probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
X is less then or equal to 1<u /><em /><u />
Answer:

Step-by-step explanation:
So we know that:

To reflect across the <em>y-axis</em>, instead of x, use -x. Therefore:

Simplify:

And that's our answer :)
Answer:
The number is 5
Step-by-step explanation:
Let x represent the number
Now let's break it down!
Sum of a number and 3 gives;
x + 3
This is then doubled to give;
2* (x + 3)
This is added to the product of 6 and the original number to give 46
Product of 6 and the original number = 6 * x
Now 2* (x + 3) is added to 6 * x to give 46
2* (x + 3) + 6*x = 46
2x + 6 + 6x = 46
8x + 6 = 46
Subtract 6 from both sides
8x + 6 - 6 = 46 - 6
8x = 40
x = 40/8
x = 5
Hence, the number is 5
<span>-1 + n=8(n+6)
Use distributive property
-1 + n= 8n + 48
Subtract n from both sides
-1= 7n + 48
Subtract 48 from both sides
-49= 7n
Divide 7 on both sides so that the only thing remaining on the right sides is the varible n.
Final Answer: -7 = n</span>