Volume of water
=6600 l=6600×0.001m³=6.6m³
▶Considering only inner volume
Let,
x↪ thickness of bottom of cuboid
Then,
↪h=3.5-x
{to get inner height of cuboid}
↪ b=1.2m-2×10cm=1.2m-0.2m=1m
{to get inner breadth of cuboid we must subtract it from 2×thickness of wall }
↪ l=2.4m-2×10cm=2.4m-0.2m=2.2m
{to get inner length of cuboid we must subtract it from 2×thickness of wall }
❇Since
↪inner volume=volume of water
↪ l×b×h=6.6
↪ 2.2×1×(3.5-x)=6.6
↪ 3.5-x=6.6/2.2
↪ x=3.5-3
↪ x=0.5m➡required thickness
Need more info to answer ?
The correct answer is D. P 720:)
The answer is C because you have three points p to Q, Q to R the two different segments then the whole thing is P to R which is also a segment.
Answer:
a ^ (1/12)
Step-by-step explanation:
a ^ (1/3)
---------------
a ^ (1/4)
We know that b^ c / b^ d = b ^ (c-d)
a^ (1/3 - 1/4)
getting a common denominator
1/3 *4/4 - 1/4*3/3 = 4/12 - 3/12
a^ (4/12 - 3/12)
a ^ (1/12)