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PilotLPTM [1.2K]
3 years ago
11

Which statements are true about the place values in the number 99.999?

Mathematics
1 answer:
allsm [11]3 years ago
5 0
Answers A. and B. Are correct
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The amount of coffee that a filling machine puts into an 8-ounce jar is normally distributed with a mean of 8.2 ounces and a sta
nordsb [41]

Answer:

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce?

This is the pvalue of Z when X = 8.2 + 0.02 = 8.22 subtracted by the pvalue of Z when X = 8.2 - 0.02 = 8.18. So

X = 8.22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.22 - 8.2}{0.018}

Z = 1.11

Z = 1.11 has a pvalue of 0.8665

X = 8.18

Z = \frac{X - \mu}{s}

Z = \frac{8.18 - 8.2}{0.018}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

0.8665 - 0.1335 = 0.7330

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

8 0
3 years ago
How do I convert these improper fractions to mixed numbers: 29/4, 13/6, 73/9, 65/8, 17/2, 5/2, 25/4, 43/7, 29/4, 73/9, 19/3, 43/
slava [35]
Divide the numerator by the denominator 
use the answer as the whole number
use the remainder as the numerator
keep the deniminator

the answers: 
7  1/4
2   1/6
8  1/8
8  1/2
2  1/2
6  1/4
6  1/7
7  1/4 (same question)
8  1/8 (same question)
6  1/3
2  1/5
9  1/10
6  1/6

5 0
3 years ago
Read 2 more answers
Of the following sets, which represents a function?
Sveta_85 [38]

Answer:

what

Step-by-step explanation:

3 0
3 years ago
Explain how you would use integer tiles to find the quotient of -15 and 3
dsp73
-5 is the answer I believe
6 0
3 years ago
Read 2 more answers
Clint is in study hall reading The hunger games. After 20 minutes, he is on page 151. After 45 minutes, he is on page 181. How m
alexdok [17]

Answer:

The number of pages had Clint read prior to study hall were <u>127 pages</u>.

Step-by-step explanation:

Given:

Clint after 20 minutes is on page 151.

And, after 45 minutes he is on page 181.

Now, to find the pages Clint read prior to study hall.

<em>The time difference = 45 minutes - 20 minutes.</em>

<em>                                  =  25 minutes.</em>

<em>Difference between the pages = 181 - 151</em>

<em>                                                     =  30 pages.</em>

If Clint is reading each page at same speed.

Then, in 25 minutes he can read = 30 pages.

So, in 1 minute he can read = 30 ÷ 25 = 1.2 pages.

Thus, in 20 minutes he can read =1.2\times 20

                                                         =24 pages.

Now, number of pages Clint had read prior to study hall = 151 - 24

                                                                                              =  127 pages.

Therefore, the number of pages had Clint read prior to study hall were <u>127 pages</u>.

7 0
3 years ago
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