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hoa [83]
3 years ago
9

Divide (-2x-3+8x^2) by (1+4x)

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

A

Step-by-step explanation:

I'm going to show you a little secret. It's called symbolab.com. You can solve almost any algebraic problem. It also gives a step by step explanation

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PLEASE HELP ASAP A bucket contains 48 fluid ounces of water. How many quarts of water does the bucket contain? Enter your answer
Ivan

Answer:

1.5 Quarts

Step-by-step explanation:

A quart contains 32 fluid ounces. So divide 48 by 32. You get 1.5.

So the bucket contains 1.5 Quarts.

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2 years ago
Answer the following question regarding the table below. 40 41 43 44 47 47 49 40 42 43 45 47 48 49 40 42 44 45 47 48 49 41 42 44
Stels [109]
Hello there, and thank you for posting your question here on brainly.

The smallest number out of the bunch is 40.

Hope this helps! 
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This morning, Megan and her dad had smoothies for breakfast. Megan made her smoothie with 1 cup of mango and 3 cups of strawberr
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Line___is a transversal.
iVinArrow [24]

Answer:

C

Step-by-step explanation:

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Read 2 more answers
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
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