Question

Assume that the probability that a baseball player will get a hit in any one at bat is 0.250. What is the probability that he will get his first hit on his 5th at bat?

Answer 1

Answer: 0.0791

Step-by-step explanation:

Given : The probability that a baseball player will get a hit in any one at bat is 0.250.

Let x be the first hit.

According to the geometric probability , the probability that x (th) trial is the first success =$P(X=x)=(1-p)^{x-1}p$ , where p is the probability of getting success in each trial.

As per given p= 0.250

Then, the probability that he will get his first hit on his 5th at bat will be :

$P(X=x)=(1-0.25)^{5-1}(0.25)\\\\=(0.75)^4(0.25)\\\\=0.0791015625\approx0.0791$

Hence, the probability that he will get his first hit on his 5th at bat is 0.0791 .